(x^2+4x+8)(2x-1)=0

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Solution for (x^2+4x+8)(2x-1)=0 equation: 


Simplifying
(x2 + 4x + 8)(2x + -1) = 0

Reorder the terms:
(8 + 4x + x2)(2x + -1) = 0

Reorder the terms:
(8 + 4x + x2)(-1 + 2x) = 0

Multiply (8 + 4x + x2) * (-1 + 2x)
(8(-1 + 2x) + 4x * (-1 + 2x) + x2(-1 + 2x)) = 0
((-1 * 8 + 2x * 8) + 4x * (-1 + 2x) + x2(-1 + 2x)) = 0
((-8 + 16x) + 4x * (-1 + 2x) + x2(-1 + 2x)) = 0
(-8 + 16x + (-1 * 4x + 2x * 4x) + x2(-1 + 2x)) = 0
(-8 + 16x + (-4x + 8x2) + x2(-1 + 2x)) = 0
(-8 + 16x + -4x + 8x2 + (-1 * x2 + 2x * x2)) = 0
(-8 + 16x + -4x + 8x2 + (-1x2 + 2x3)) = 0

Combine like terms: 16x + -4x = 12x
(-8 + 12x + 8x2 + -1x2 + 2x3) = 0

Combine like terms: 8x2 + -1x2 = 7x2
(-8 + 12x + 7x2 + 2x3) = 0

Solving
-8 + 12x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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